Calculate the total pressure in a mixture og `8 g` of oxygen and `4 g` hydrogen confined in a vessel of `1 dm^(3)` at `27^(@)C`. `(R = 0.083 "bar" dm^(3) K^(-1) mol^(-1))`

Options

A. 28.5 bar
B. 56.025 bar
C. 112.5 bar
D. 14.25 bar

Answer

B

Explanation

`P_(T) P_(V) = n_(T) RT : P = (n_(T) RT)/(V)`
`n_(T) = n_(O_(2)) + n_(H_(2)) = (2.5 xx 0.083 xx 300)/(1)`
`(8)/(32) + (4)/(2) = 2.5 = 56.025` bar