At a temperature `T, K`, the pressure of `4.0 gm` argon in a bulb is `P`. The bulb is put in a bath having temperature higher by `50 K` than the first one `0.8` of argon gas had to be removed to maintain original pressure. The temperature `T` is

Options

A. 73 K
B. 100 K
C. 200 K
D. 510 K

Answer

C

Explanation

At constant P and V , `n_(1) T_(1) = n_(2) T_(2)`
`4 xx T_(1) = 3.2 xx (T_(1) + 50)`
On solving , `T_(1)= 200` K