24 ml of water gas containing only hydrogen and carbon monoxide in equal proportions by volume are exploded with 80 ml of air in which 20% by volume is `O_2` , if all gasesous are measured at room temperature and pressure , calculate the composition by volume of the unreacted resulting gaseous mixture .

Options

A. `O_(2) to 12 mlN_(2) to 64 ml CO_(2) to 4 ml`
B. `O_(2) to 4 ml N_(2) to 12 ml CO_(2) to 64 ml`
C. `O_(2) to 64 ml N_(2) to 4 ml CO_(2) to 12 ml`
D. `O_(2) to 4 mlN_(2) to 64 ml CO_(2) to 12 ml`

Answer

D

Explanation

`underset("2 volume") underset(12) (2 H_(2)) + underset("1 volume") underset(6) (O_(2)) to underset("zero volume") (2 H_(2) O) `(liq)
(ii) `underset(" 2 volume") underset(12) (2 CO) + underset(" 1 volume") underset(6) (O_(2)) to underset(2 " volume") (2 CO_(2)) (12 ml)`
Total oxygen used 6 +6= 12 ml
Total oxygen present in 80 ml of air = `80 xx 20//100 = 16 ` ml
Un used = 4 ml
`N_(2) = 64` ml
`CO_(2) = 12` ml