What will be the pressure exerted by a mixture of `3.2 g` of methane and `4.4g` of carbon dixide contained in a `9 dm^(3)` flask at `27^(@)C` ? .

Options

A. `8.314` Pa
B. `8.314 xx 10^(2)` Pa
C. `2 xx 10^(2)` Pa
D. `8.314 xx 10^(4)` Pa

Answer

D

Explanation

`because PV = n_(1) RT`
`therefore " " n_(T) = n_("Methane") + n_(CO_(2))`
`therefore P = (n_(T) RT)/(v) = (3.2)/(16) + (4.4)/(44) = 0.3`
`= (0.3 xx 0.082 xx 300)/(9) = 8.2 xx 10^(4)` Pa