A vessel contains 1 mole of `O_(2)` at `27^(@)C` and 1 atm pressure. A certain amount of the gas was withdrawn and the vessel was heated to `327^(@)C` to maintain the pressure of 1 atm. The amount of gas removed was

Options

A. 0.2 mole
B. 0.5 mole
C. 0.25 mole
D. 0.1 mole

Answer

B

Explanation

`P_(1) V_(1) = n_(1) RT_(1)`
`P_(2) V_(2) = n_(2) RT _(2)`
`P_(1) = P_(2) , V_(1) = V_(2)`
`because n_(1) T_(1) = n_(2) T_(2)`
`n_(2) = (300)/(600) = (1)/(2) = 0.5` moles