The pressure and temperature of `4 dm^(3)` of carbon dioxide gas are doubled. Then the volume of carbon dioxide gas would be

Options

A. `2 dm^(3)`
B. `3 dm^(3)`
C. `4 dm^(3)`
D. `8 dm^(3)`

Answer

C

Explanation

`(p_(1) V_(1))/(T_(1)) = (p_(2) V_(2))/(T_(2)) = (p_(1) xx 4)/(T_(1)) = (2p_(1) xx V_(2))/(2 T_(1))`
` 2V_(2) = 8 , V_(2) = 4 dm^(3)`