By the ideal gas law, the pressure of 0....

By the ideal gas law, the pressure of 0.60 mole `NH_3` gas in a 3.00 L vessel at `25^@C` is

`48.9` atm

`4.89` atm

`0.489` atm

`489` atm

Text Solution

Verified by Experts

The correct Answer is:

`p V = nRT
or p = `(nRT)/(V)`
`= (0.60 xx 0.821 xx 298)/(3) = 4.89` atm .

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