Given: rms velocity of hydrogen at 300K is `1.9 xx 10^3` m/s. The rms velocity of oxygen at 1200K will be

Options

A. `7.6 xx 10^(3)` m/s
B. `3.8 xx 10^(3)` m/s
C. `0.95 xx 10^3` m/s
D. `0.475 xx 10^(3)` m/s

Answer

C

Explanation

`v_(rms) (H_(2)) = sqrt((3R xx 300)/(2)) = 1.9 xx 10^(3)` m/s
`r_(rms) (O_(2)) = sqrt((3R xx 1200)/(32)) = (2)/(4) ( sqrt((3R xx 300)/(2)))`
`= (1)/(2) (1.9 xx 10^(3)) m//s = 0.95 xx 10^(3) m//s`