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At what temperature, the r.m.s. velocity...

At what temperature, the r.m.s. velocity of a gas measured at `50^(@)C` will become double ?

A

626 K

B

1019 K

C

`200^(@) C`

D

`1019^(@) C`

Text Solution

Verified by Experts

The correct Answer is:
D
`r_(rms) = sqrt((3RT)/(M))`
Where T is in Kelvin scale .
For rms velocity to be doubled , T in Kelvin scale is raised 4 times . So it should be `4 xx (50 + 273) = 1292 K = 1292 - 273 = 1019^(@) C` .
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