What will happen to volume of a bubble of air found under water in a lake where temperature is `15^(@)C` and the pressure is 1.5 atm, if the bubble rises to the surface where the temperature is `25^(@)C` and the pressure is 1.0 atm?

Options

A. Its volume will become greater by a factor of 2.5
B. Its volume will become greater by a factor of 1.6
C. Its volume will become greater by a factor of 1.1
D. Its volume will become smallest by a factor of 0.70

Answer

B

Explanation

`(P_(1) V_(1))/(P_(2) V_(2))/(T_(2)) = (1.5 "atm" xx V)/(288 K) = (1 xx "atm" xx V_(2))/(298 K)`
`therefore V_(2) = 1.6 V `