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A certain gas takes three times as long ...

A certain gas takes three times as long to effuse out as helium. Its molar mass will be

A

64 u

B

9 u

C

27 u

D

36 u

Text Solution

Verified by Experts

The correct Answer is:
D
`(r_(He))/(R_(X)) = sqrt((M_(X))/(M_(He))) or (V//t _(He))/(V// t_(X)) = sqrt((M_(X))/(M_(He)))`
or `(t_(X))/(t_(He)) = sqrt((M_(X))/(M_(He)))`
`therefore (3)/(1) = sqrt((M_(x))/(4) ` or `(M_(x))/(4) = 9` or `M_(X) = 36`
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