Equal masses of `H_(2)`, `O_(2)` and methane have been taken in a container of volume `V` at temperature `27^(@)C` in identical conditions. The ratio of the volume of gases `H_(2) : O_(2)` : methane would be

Options

A. `8 : 1 : 2`
B. `8 : 16 : 1`
C. `16 : 8 : 1`
D. `16 : 1 : 2`

Answer

D

Explanation

Let mass of each gas = 1 gm and volume ratio of each gas is same as their mole ratio
`n_(H_(2)) : n_(O_(2)) : n_(CH_(2)) = (1)/(2) : (1)/(32) : (1)/(16) = 16 : 1 : 2`