Equal moles of hydrogen and oxygen gases are placed in a container with a pin-hole through which both can escape. What fraction of the oxygen escapes in the time required for one-half of the hydrogen to escape ?

Options

A. `1//8`
B. `1//4`
C. `3//8`
D. `1//2`

Answer

A

Explanation

Ratio of moles diffused = Ratio of rates of diffusion
`(n_("Oxygen"))/(n_("Hydrogen")) = (r_("Oxygen"))/(r_("Hydrogen")) = (1)/(4)`
`n_("Oxygen") = n_("Hydrogen") xx (1)/(4) = (1)/(2) xx (1)/(4) = (1)/(8)`