When `0.1` mole of an acid is added to `2 L` of a buffer solution, the `P^(H)` of the buffer decreases by `0.5`. The buffer capacity of the solution is

Options

A. 0.6
B. 0.4
C. 0.2
D. 0.1

Answer

D

Explanation

buffer capacity
`=("no.of moles of an acid added per lit solution")/(P^(H)"change")`
0.1 mole of an acid is added to 2. lit of a buffer.
1. lit of a buffer contanis how many moles?
`=(1xx0.1)/(2)=0.05`
`P^(H)` change =0.5
`:.` Buffer capacity `=(0.05)/(0.5)=0.1`