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100 mL of 0.15 M HCl is mixed with 100 m...

`100 mL` of `0.15 M HCl` is mixed with `100 mL` of `0.005M HCl` , what is the `pH` of the following solution approxmately

A

`2.5`

B

`1.15`

C

2

D

4

Text Solution

Verified by Experts

The correct Answer is:
B

`[H^(+)]=(V_(1)N_(1)+V_(2)N_(2))/((V_(1)+V_(2)))`
`[H^(+)]=0.00775 " P^(H)=1.5`
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NARAYNA-ACIDS & BASES-EXERCISE-II (P^(H) Problems)
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  13. The degree of dissociation of 0.1N CH(3)COOH is (K(a)= 1xx10^(-5))

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  14. The pH of the 10^(-3)M NH(4)OH(Kb = 10^(-5)) is

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  18. Equal volums of solutions pH values 1,3,5,6 are mixed with each other ...

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  19. The p^(H) of HCl is 3. Then the P^(H) of NaOH solution having same mol...

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