The `P^(H)` of `0.01 M` solution of acetic acid is `5.0` What are the values of `[H^(+)]` and `Ka` respectively ?

Options

A. `2X10^(-4)M, 2X10^(-8)`
B. `1X10^(-5)M 1X10^(-9)`
C. `1X10^(-5)M,1X10^(-8)`
D. `1X10^(-4)M,1x10^(-6)`

Answer

C

Explanation

`[H^(+)]=10^(-PH)=10^(-5)`
`= sqrt(K axxc) " " ( :. C=0.01M)`
`rArr Ka=([H^(+)]^(2))/(C)=(10^(-10))/(10^(-2))=10^(-8)`