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The degree of dissociation of 0.1N CH(3)...

The degree of dissociation of `0.1N CH_(3)COOH` is `(K_(a)= 1xx10^(-5))`

A

`10^(-6)`

B

`10^(-7)`

C

`10^(-3)`

D

`10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
D
`alpha= sqrt((Ka)/(C))= sqrt((1xx10^(-5))/(0.1))= sqrt(10^(-4))=10^(-2)`
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