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In the equilibrium A^(-)+H(2)OhArrHA+OH^...

In the equilibrium `A^(-)+H_(2)OhArrHA+OH^(-)(K_(a)=1.0xx10^(-5))`. The degree of hydrolysis of `0.001 M` solution of the salt is

A

`10^(-3)`

B

`10^(-4)`

C

`10^(-5)`

D

`10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(a)=1.0xx10^(-5),K_(h)`= hydrolysis constant
degree of hydrolysis
`(h)=sqrt((K_(h))/(C))=sqrt((10^(-9))/(0.001))`
`= sqrt(10^(-6))=10^(-3), " " h=10^(-3)`
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