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The pK(a) of HCN is 9.30. The pH of a so...

The `pK_(a)` of `HCN` is 9.30. The pH of a solutin prepared by mixing `2.5` moles of `KCN` and `2.5` moles of `HCN` in water and making up the total volume to `500 mL` is

A

`9.30`

B

`7.30`

C

`10.30`

D

`8.30`

Text Solution

Verified by Experts

The correct Answer is:
A
In the Henderson.s equation.
`pH=pK_(a)+"log"(["salt"])/(["acid"])=9.3+"log" ([2.5])/([2.5])`
`p^(H)=9.3`
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