The maximum pH of a solution which is `0.10 M` is `Mg^(2+)` from which `Mg(OH)_(2)` is not precipitated is [`K_(sp)` of `Mg(OH)_(2) = 1.2 xx 10^(-11) M^(3)`]

Options

A. `4.26`
B. `6.96`
C. `7.04`
D. `9.04`

Answer

D

Explanation

For `Mg(OH)_(2)` not be precipitated
`[OH^(-)] lt [(K_(sp)(Mg(OH)_(2)))/([Mg^(2+)])^(1//2)`
`[OH^(-)]lt [(1.2x10^(-11)M^(3))/(0.10M)]^(1//3) lt 1.035xx10^(-5)M`
`pOH lt 4.36, pH gt 14-4.36=9.04`