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The equilibrium constant for the reactio...

The equilibrium constant for the reaction `2x+y Leftrightarrow x_(2)y" is 10"L^(2) mol^(-2)`. The rate constant for the back ward reaction `2.8 s^(-1)`. What is the rate constant of the forward reaction?

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Equilibrium constant, `K_(c)=10=(K_(f))(K_(b))=(K_(f))/(2.8)`
Forward rate constant `K_(f)=28L^(2)" mol"^(2)s^(-1)`
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