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A reaction CaF(2)hArrCa^(2+)+2F^(-) is a...

A reaction `CaF_(2)hArrCa^(2+)+2F^(-)` is at equilibrium. If the concentration of `Ca^(2+)` is increased four times, what will be the change in `F^(-)` concentration as compared to the initial concentration of `F^(-)`?

A

One half of its initial value

B

Twice the initial value

C

1/4th of its initial value

D

Thrice of its initial value

Text Solution

Verified by Experts

The correct Answer is:
A
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