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N(2)+3H(2) Leftrightarrow 2NH(3) in this...

`N_(2)+3H_(2) Leftrightarrow 2NH_(3)` in this equilibrium system if the pressure is increased at `25^(@)C` then the value of K will

A

Increases

B

Decreases

C

Remains the same

D

Depends on the nature of the reactants

Text Solution

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The correct Answer is:
To solve the question regarding the effect of increased pressure on the equilibrium constant \( K \) for the reaction \[ N_2 + 3H_2 \leftrightarrow 2NH_3 \] we can follow these steps: ### Step 1: Understand the Reaction The given reaction involves the formation of ammonia (\( NH_3 \)) from nitrogen (\( N_2 \)) and hydrogen (\( H_2 \)). The balanced equation shows that 1 mole of nitrogen reacts with 3 moles of hydrogen to produce 2 moles of ammonia. ### Step 2: Write the Expression for the Equilibrium Constant The equilibrium constant \( K_c \) for this reaction can be expressed as: \[ K_c = \frac{[NH_3]^2}{[N_2][H_2]^3} \] Where: - \([NH_3]\) is the concentration of ammonia, - \([N_2]\) is the concentration of nitrogen, - \([H_2]\) is the concentration of hydrogen. ### Step 3: Analyze the Effect of Pressure According to Le Chatelier's principle, if the pressure of a gaseous equilibrium system is increased, the system will shift in the direction that produces fewer moles of gas. In this reaction: - Reactants: \( 1 \, N_2 + 3 \, H_2 = 4 \, \text{moles of gas} \) - Products: \( 2 \, NH_3 = 2 \, \text{moles of gas} \) Since there are 4 moles of gas on the reactant side and 2 moles of gas on the product side, an increase in pressure will shift the equilibrium to the right, favoring the production of ammonia. ### Step 4: Determine the Effect on the Equilibrium Constant \( K_c \) However, it is crucial to note that the equilibrium constant \( K_c \) is only affected by changes in temperature. The value of \( K_c \) remains constant regardless of changes in pressure or volume. Thus, even though the equilibrium position shifts to the right with increased pressure, the actual value of \( K_c \) does not change. ### Conclusion Therefore, the value of \( K \) (or \( K_c \)) remains the same when the pressure is increased at \( 25^\circ C \). ### Final Answer The value of \( K \) will remain the same. ---
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NARAYNA-CHEMICAL EQUILIBRIUM-Exercise -I (C.W.)
  1. In the process N(2)+3H Leftrightarrow 2NH(3), the initial concentratio...

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  2. The equilibrium constant of a reaction at 298 K is 5 xx 10^(-3) and at...

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  3. N(2)+3H(2) Leftrightarrow 2NH(3) in this equilibrium system if the pre...

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  4. A((s))+B((g)) +" heat "Leftrightarrow 2C((s))+2D((g)). At equilibrium ...

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  5. For A(2(g))+B(2(g)) underset(K(b)=15)overset(K(f)=5) Leftrightarrow 2A...

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  6. The equilibrium constant for a reaction A+2B hArr 2C is 40. The equi...

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  7. The equilibrium constant for the reaction N(2(g))+O(2(g)) Leftrightarr...

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  8. In a reversible reaction, if the concentration of reactants are double...

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  9. The unit for the equilibrium constant of the reaction

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  10. For the equilibrium N(2)(g)+3H(2)(g) Leftrightarrow 2NH(3)(g)" at "100...

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  11. In which of the following reactions, will the equilibrium mixture cont...

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  12. The unit of equilibrium constant, K for the reaction, A+B rarr C , wou...

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  13. The equilibrium constant for the reversible reaction N(2)+3H(2) hArr 2...

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  14. The active mass of 64g of HI In a 2Lit flask would be

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  15. AB(3)(g) is dissociation as AB(2)(g) hArr AB(2)(g)+(1)/(2)B(2)(g), W...

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  16. In which one of the following gaseous equilibrium, K(p) is less than K...

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  17. In the reaction H(2(g)) +l(2(g)) Leftrightarrow 2HI((g))

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  18. The equilibrium of the reaction N(2)(g)+3H(2)(g) hArr 2NH(3)(g) will b...

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  19. Consider the following equilibrium PCl(5(g)) Leftrightarrow PCl(3(g))+...

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  20. One mole of A (g) is heated to 200^@ C in a one litre closed flask, ti...

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