If `K_(1)` and `K_(2)` are the equilibrium constants of the equilibria (a) and (b) respectivel, what is the relationship between the two constants ?
(a) `SO_(2)+(1)/(2) O_(2)(g)hArr SO_(3)(g),K_(1)`
(b) `2SO_(3)(g) hArr 2SO_(2)(g)+O_(2)(g),K_(2)`

Options

A. `K_(1)=K_(2)`
B. `K_(1)=(1)/(K_(2))`
C. `K_(2)=K_(1)^(2)`
D. `K_(1)^(2)=(1)/(K_(2))`

Answer

D

Explanation

`K_(1)=(SO_(3))/([SO_(2)] [O_(2)]^(1/2)), K_(2)=([SO_(2)]^(2) [O_(2)])/([SO_(3)]^(2))`