One mole of `SO_(3)` was placed in a litre reaction vessel at a certain temperature. The following equilibrium was established `2SO_(3)(g)hArr 2SO_(2)(g)+O_(2)(g)` At equilibrium 0.6 moles of `SO_(2)` were formed. The equilibrium constant of the reaction will be

Options

A. 0.36
B. 0.45
C. 0.54
D. 0.675

Answer

D

Explanation

`2SO_(3) Leftrightarow 2SO_(2)+O_(2)`
`{:(,"initial",1,0,0),(,"at equil",1-2x,2x,0),(,"given that",2x=0.6,x=0.3):}`
`k_(c)=([SO_(2)]^(2) [O_(2)])/([SO_(3)]^(2))`