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When CO(2) dissolves in water, the follo...

When `CO_(2)` dissolves in water, the following equilibrium is established.
`CO_(2)+2H_(2)O hArr H_(3)O^(+) +HCO_(3)^(-)`
for which the equilibrium constant is `3.8 xx 10^(-6)` and pH 6.0. What would be the ratio of concentration of bicarbonate ion to carbon dioxide `i.e.[HCO_(3)^(-)]//[CO_(2)]`

A

`3 x 10^(-1)`

B

`3.8 x 10^(-13)`

C

`13.4`

D

6

Text Solution

Verified by Experts

The correct Answer is:
A
`"given that "p^(H)=6`
`rArr [H_(3)O^+]=10^(-6)`
`3.8 xx 10^(-7)= [(H_(3)O^(+)] [HCO_(3)^(-)])/([CO_(2)])`
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