Given the reaction between 2 gases represented by `A_(2)` and `B_(2)` to given the compound AB(g). `A_(2)(g) + B_(2)(g)hArr 2AB(g)`
At equilibrium, the concentrtation
of `A_(2) = 3.0xx10^(-3) M`
of `B_(2) = 4.2xx10^(-3) M`
of `AB = 2.8xx10^(-3) M`
If the reaction takes place in a sealed vessel at `527^(@)C` . then the value of `K_(c)` will be

Options

A. 2
B. 1.9
C. 0.62
D. 4.5

Explanation

The given reaction `A_(2)+B_(2) Leftrightarrow 2AB`
`K_(c)=([AB]^(2))/([A_(2)] [B_(2)]) =((2.8 xx 10^(-3))^(2))/((3 xx 10^(-3)) xx (4.2 xx 10^(-3))=0.62 `