Among the following the aromatic compound is

Options

A.
B.
C.
D.

Explanation

To determine which of the given compounds is aromatic, we will apply Huckel's rule and check the necessary conditions for aromaticity.

### Step-by-Step Solution:

1. **Identify the Compounds**: First, we need to clearly identify the compounds listed in options A, B, C, and D. For the sake of this solution, let's assume they are labeled as follows:
- Option A: Compound 1
- Option B: Compound 2
- Option C: Compound 3
- Option D: Compound 4

2. **Check for Cyclic Structure**: For a compound to be aromatic, it must be cyclic. We will examine each compound to see if it has a ring structure.

3. **Hybridization of Atoms**: All atoms in the cyclic structure must be sp² hybridized. We will analyze the hybridization of the atoms in each compound.

4. **Planarity**: The compound must be planar, which is typically satisfied if all the involved atoms are sp² hybridized.

5. **Count the Pi Electrons**: We will count the number of pi electrons in the cyclic structure. Each double bond contributes 2 pi electrons.

6. **Apply Huckel's Rule**: According to Huckel's rule, a compound is aromatic if it has a cyclic cloud of pi electrons that follows the formula \(4n + 2\) where \(n\) is a non-negative integer (0, 1, 2, ...). We will check if the number of pi electrons in each compound fits this formula.

7. **Determine Aromaticity**:
- If a compound has \(4n + 2\) pi electrons, it is aromatic.
- If it has \(4n\) pi electrons, it is anti-aromatic.
- If it does not meet these criteria, it is non-aromatic.

8. **Conclusion**: After analyzing all the compounds, we will conclude which one is aromatic based on the above criteria.

### Example Analysis:
- **Option A**: Assume it has 6 pi electrons (which is \(4(1) + 2\)). This compound is aromatic.
- **Option B**: Assume it has 4 pi electrons (which is \(4(1)\)). This compound is anti-aromatic.
- **Option C**: Assume it has 2 pi electrons (which is \(4(0) + 2\)). This compound is aromatic.
- **Option D**: Assume it has 8 pi electrons (which is \(4(2)\)). This compound is anti-aromatic.

### Final Answer:
Based on the analysis, if Option A has 6 pi electrons and Option C has 2 pi electrons, both A and C are aromatic. However, if the question asks for only one aromatic compound, we would select the one that is most commonly recognized as aromatic, which is typically the one with 6 pi electrons.