Product [P] in the reaction is
`CH_(3)-CH_(2)-Mg-Cl overset(C_(6)H_(5)OH)rarr[P]`

Options

A. Benzene
B. Ethane
C. Methane
D. Napthalene

Answer

To determine the product [P] in the reaction `CH3-CH2-Mg-Cl + C6H5OH → [P]`, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- We have an organomagnesium compound (Grignard reagent) `CH3-CH2-Mg-Cl` and phenol `C6H5OH`.

2. **Understand the Nature of the Grignard Reagent**:
- The Grignard reagent `CH3-CH2-Mg-Cl` acts as a nucleophile due to the presence of the carbon atom bonded to magnesium. The carbon is partially negative, making it reactive towards electrophiles.

3. **Identify the Electrophile**:
- In this case, phenol `C6H5OH` contains an acidic hydrogen (the hydrogen attached to the oxygen). This hydrogen can be abstracted by the nucleophilic carbon from the Grignard reagent.

4. **Reaction Mechanism**:
- The nucleophilic carbon from the Grignard reagent attacks the acidic hydrogen of phenol, leading to the formation of a phenoxide ion and a new carbon-carbon bond.
- The reaction can be represented as:
\[ CH3-CH2-Mg-Cl + C6H5OH \rightarrow C6H5O^{-} + CH3-CH2-H \]
- Here, the `C6H5O^-` is the phenoxide ion formed after the deprotonation of phenol.

5. **Formation of the Product**:
- The product [P] will be the alkane formed from the Grignard reagent and the phenoxide ion. The alkane formed here is ethane (C2H6) since the Grignard reagent contributes the ethyl group (C2H5) to the reaction.

6. **Final Product**:
- Therefore, the final product [P] is:
\[ C6H5-CH2-CH3 \]
- This indicates that the product is ethyl phenyl ether (C6H5-CH2-CH3).

### Conclusion:
The product [P] in the reaction is ethyl phenyl ether.