In an aquatic ecosystem having pollution of DDT and garbage, COD will be

Options

A. Less than BOD
B. More than BOD
C. Equal to BOD
D. Half of BOD

Answer

To solve the question regarding the Chemical Oxygen Demand (COD) in an aquatic ecosystem polluted with DDT and garbage, we can follow these steps:

### Step 1: Understand COD and BOD
- **COD (Chemical Oxygen Demand)** measures the amount of oxygen required to chemically oxidize organic and inorganic matter in water.
- **BOD (Biological Oxygen Demand)** measures the amount of oxygen required by microorganisms to decompose organic matter in water.

### Step 2: Identify the pollutants
- The pollutants mentioned are **DDT (Dichloro-Diphenyl-Trichloroethane)**, which is a synthetic pesticide, and **garbage**, which can include various organic and inorganic materials.

### Step 3: Analyze the impact of pollutants on COD
- DDT is a persistent organic pollutant that does not easily break down. Its presence in water increases the demand for oxygen as it requires chemical processes to degrade.
- Garbage can introduce a variety of organic materials that also require oxygen for decomposition.

### Step 4: Compare COD and BOD
- In an ecosystem with high levels of DDT and garbage, the chemical breakdown of these pollutants will require more oxygen. Therefore, the COD will be higher than the BOD.
- This is because COD accounts for all the oxygen required to chemically oxidize both the DDT and the organic waste, while BOD only accounts for the oxygen consumed by microorganisms.

### Step 5: Conclusion
- Given that the presence of DDT and garbage increases the demand for oxygen, we can conclude that the COD will be significantly higher than the BOD in this polluted aquatic ecosystem.

### Final Answer
- The value of COD in an aquatic ecosystem polluted with DDT and garbage will be **higher than the BOD**.

---