Home
Class 12
CHEMISTRY
Rate constant of a first order reaction ...

Rate constant of a first order reaction is `0.0693" m in"^(-1)`. If we start with `20" mol L"^(-1)` concentration in what time, it is reduced to `2.5" mol L"^(-1)` ?

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    NARAYNA|Exercise EVALUATE YOURSELF - 4|2 Videos
  • CHEMICAL KINETICS

    NARAYNA|Exercise EVALUATE YOURSELF - 6|4 Videos
  • CHEMICAL KINETICS

    NARAYNA|Exercise EVALUATE YOURSELF - 2|3 Videos
  • CARBOXYLIC ACID

    NARAYNA|Exercise All Questions|288 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    NARAYNA|Exercise ASSERTION & REASON TYPE QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

Rate constant of a reaction is 0.0693" min"^(-1) . Starting with 10" mol L"^(-1) , rate of reaction after 10 minutes will be

The rate constant of a reaction is 0.0693 min^(-1) . Starting with 10 mol , the rate of the reaction after 10 min is

The rate constant of a reaction with respect to the reactant A is 6 "min"^(-1) . If we start with [A] = 0.8 mol L^(-1) , when would [A] reach the value of 0.08 mol^(-1) ?

The rate constant of a first order reaction is 2.0 xx 10^(-5)s^(-1) and the initial concentration is 0.10 mol L^(-1) . The initial rate is

A first order reaction with respect to reactant A , has a rate constant 6" min"^(-1) . If we start with [A]=0.5 "mol L"^(-1) , when would [A] reach the value 0.05" mol L"^(-1)

The specific rate constant for a first order reaction is 1 times 10^–3 sec^–1 . If the initial concentration of the reactant is 0.1 mole/lt, the rate of reaction mol l^–1 sec^–1 is:

The specific rate constant for a first order reaction is 1 times 10^–3 sec^–1 . If the initial concentration of the reactant is 0.1 mole per litre the rate (in mol l^-1 sec^-1 ) is: