Home
Class 12
CHEMISTRY
Rate constant of two reactions are given...

Rate constant of two reactions are given below. Indentifying their order of reaction.
(i) `k = 6.3 xx 10^(-2) L mol^(-1) s^(-1)`
(ii) `k = 2.8 xx 10^(-4) s^(-1)`

A

one

B

zero

C

two

D

fractional

Text Solution

Verified by Experts

The correct Answer is:
B
For zero order reactions rate is independent of concentrations.
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL KINETICS

    NARAYNA|Exercise EXERCISE -1 (H.W) MOLECULARITY|3 Videos

  • CHEMICAL KINETICS

    NARAYNA|Exercise EXERCISE -1 (H.W) HALF LIFE|6 Videos

  • CHEMICAL KINETICS

    NARAYNA|Exercise EXERCISE -1 (H.W) RATE OF REACTION & FACTORS|7 Videos

  • CARBOXYLIC ACID

    NARAYNA|Exercise All Questions|288 Videos

  • CHEMISTRY IN EVERYDAY LIFE

    NARAYNA|Exercise ASSERTION & REASON TYPE QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

Rate constant of two reactions are given below. Identifying their order of reaction k = 5.3 xx 10^(-2) L mol^(-1) s^(-1) k = 3.8 xx 10^(-4) s^(-1)

Identify the reaction order from each of the following rate constants. (i) k = 2.3xx10^(-5)Lmol^(-1)s^(-1) (ii) k = 3xx 10^(-4)s^(-1)

Identify the order of a reaction for each of the following rate constants: i) k=2.3 xx 10^(-5)L mol^(-1)s^(-1) ii) k= 3 xx 10^(4)s^(-1) .

Identify the reaction order from each of the following rate. i) k=2.3 xx 10^(5) L mol^(-1)s^(-1) ii) k=2.3 xx 10^(5)Lmol^(-1)s^(-1) ii) k=3.1 xx 10^(-4)s^(-1)

For a decomposition, the values of rate constants at two different temperature are given below: k_(1) = 2.15 xx 10^(-8)L mol^(-1)s^(-1) at 650 K k_(2) = 2.39 xx 10^(-7) L mol^(-1)s^(-1) at 700 K Calculate the value of activation energy for the reaction (R= 8.314 JK^(-1) mol^(-1))

Rate constant of a reaction is 3.6 xx 10^-3 s^-1 . The order of reaction is _____