At particular concentration , the half life of the reaction is 100 minutes. When the concentration of the reactant become double half life becomes , 25 minutes , then what will be the order of the reaction ?

Options

A. zero
B. 0.5
C. 2
D. 1

Answer

C

Explanation

From the given data,
`t_(1/2)/t_(1/2) = (a_(2)/a_(1))^(n-1)`
So the reaction is the second order.