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The chemical reaction 2O(3)rarr3O(2) pro...

The chemical reaction `2O_(3)rarr3O_(2)` proceeds as follows :
`O_(3)rarrO_(2)O" "` (fast)
`O+O_(3)rarr2O_(2)" "` (slow)
The rate law expression should be :

A

Rate `=K[O_(3)]^(2)`

B

Rate `=K[O_(3)]^(2) [O_(2)]^(-1)`

C

Rate `=K[O_(3)][O_(2)]`

D

Rate `=K[O_(3)][O_(2)]^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`O + O_(3) overset("slow") to 2O_(2)`
`r=K_(1)[O][O_(3)]`
`=K_(1)(K_( c)[O_(3)][O_(3)])/([O_(2)])`
`=K[O_(3)]^(2)[O_(2)]^(-1)`
`O_(3) `K_( c) =([O_(2)][O])/([O_(3)])`
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