For a non-equilibrium process `A + B to` Produts the rate is first order with respect to A and second order with respect to B. If 1.0 Mole each of A and B are introduced into a one liter vessel and the intial rate is `1.0 xx 10^(-2)`mol `L^(-1)s^(-1)`, the rate when half of the reaction have been eonsumed is:

Options

A. `1 xx 10^(-2)"mol"."lit"^(-1).s^(-1)`
B. `2.5 xx 10^(-3) "mol"."lit"^(-1).s^(-1)`
C. `5.0 xx 10^(-2) "mol"."lit"^(-1).s^(-1)`
D. `0.5 xx 10^(-2) "mol"."lit"^(-1)s^(-1)`

Answer

B

Explanation

`K = 1 xx 10^(-2) "lit"."mol"^(-1).s^(-1)`
Rate `=K[A]^(2)[B]^(0)`
W hen 50% of the reactants are converted into products
rate `=1 xx 10^(-2)(0.5)^(2) = 2.5 xx 10^(-3)"mol"."lit"^(-1)s^(-1)`