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4Zn+10HNO(3)rarr4Zn(NO(3))(2)+NH(4)NO(3)...

`4Zn+10HNO_(3)rarr4Zn(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O`. In this reaction one mole of `HNO_(3)` is reduced by

A

32g Zn

B

64g Zn

C

128g Zn

D

256g Zn

Text Solution

Verified by Experts

The correct Answer is:
D
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