`CH_3-overset(O)overset(||)C-CH_3+NaOHunderset(Delta)overset(I_2)rarr(A)`. A will be

Options

A. `CH_3OH`
B. `CHI_3`
C. `CH_3CI_3`
D. `CH_3CH_2CI_3`

Explanation

To solve the given reaction, we need to analyze the reaction of acetone with sodium hydroxide (NaOH) in the presence of iodine (I2) under heat. The process involves the formation of an intermediate and subsequent substitution reactions. Here’s a step-by-step breakdown:

### Step 1: Identify the Reactants
The reactant given is acetone, which has the structure CH3COCH3. We are reacting it with NaOH and I2.

### Step 2: Deprotonation
When acetone reacts with NaOH, the hydroxide ion (OH-) abstracts a proton (H+) from one of the methyl groups adjacent to the carbonyl group. This results in the formation of an enolate ion:
\[ \text{CH}_3\text{COCH}_3 + \text{NaOH} \rightarrow \text{CH}_3\text{COCH}_2^{-} + \text{Na}^+ + \text{H}_2\text{O} \]

### Step 3: Resonance Stabilization
The enolate ion (CH3COCH2-) is resonance stabilized. The negative charge can be delocalized between the carbonyl oxygen and the carbon atom adjacent to it, which enhances the stability of the enolate.

### Step 4: Iodination
The enolate ion (CH3COCH2-) can now attack iodine (I2). The nucleophilic carbon (with the negative charge) attacks one of the iodine atoms, leading to the formation of an iodo compound:
\[ \text{CH}_3\text{COCH}_2^{-} + \text{I}_2 \rightarrow \text{CH}_3\text{COCH}_2\text{I} + \text{I}^- \]

### Step 5: Further Iodination
If there is excess iodine and NaOH, the process can repeat. The remaining hydrogen on the carbon adjacent to the carbonyl can be abstracted again, leading to another enolate formation, which can then react with another iodine molecule:
\[ \text{CH}_3\text{COCH}_2\text{I} + \text{NaOH} + \text{I}_2 \rightarrow \text{CH}_3\text{COCH}\text{I}_2 + \text{Na}^+ + \text{H}_2\text{O} \]

### Final Product
The final product (A) of the reaction is:
\[ \text{CH}_3\text{COCH}\text{I}_2 \]

### Summary of the Reaction
The overall reaction can be summarized as:
\[ \text{CH}_3\text{COCH}_3 + \text{NaOH} + \text{I}_2 \xrightarrow{\Delta} \text{CH}_3\text{COCH}\text{I}_2 \]