`C_2H_5OH+CaOCl_2overset(H_2O)rarr(A)`. A will be

Options

A. `CH_3CHO`
B. `CH_3CH_2I`
C. `CH_3CH_2Cl`
D. `CHCl_2`

Answer

To solve the question regarding the reaction of ethanol (C2H5OH) with calcium oxychloride (Ca(OCl)2) in the presence of water, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethanol (C2H5OH) and calcium oxychloride (Ca(OCl)2). Ethanol is an alcohol, and calcium oxychloride is a bleaching agent that can facilitate the conversion of alcohols into carbonyl compounds.

**Hint:** Look for the functional groups in the reactants to predict the possible products.

### Step 2: Understand the Reaction Conditions
The presence of water (H2O) indicates that the reaction is occurring in an aqueous medium. This can influence the types of products formed, as water can participate in the reaction.

**Hint:** Consider how water can affect the reaction mechanism and the products formed.

### Step 3: Predict the Products
When ethanol reacts with calcium oxychloride, it can undergo oxidation. The reaction typically leads to the formation of chloroform (CHCl3) and calcium formate (Ca(HCOO)2). The balanced equation for this reaction can be represented as:

\[ C_2H_5OH + Ca(OCl)_2 \rightarrow CHCl_3 + Ca(HCOO)_2 \]

**Hint:** Think about the typical products formed when alcohols react with oxidizing agents.

### Step 4: Identify Product A
From the products formed in the reaction, we can see that one of the products is chloroform (CHCl3). Therefore, product A in the question is chloroform.

**Hint:** Check the list of options provided in the question to match the identified product.

### Conclusion
The product A formed from the reaction of ethanol with calcium oxychloride in the presence of water is chloroform (CHCl3).

### Final Answer
A = CHCl3 (Chloroform)