Which one of the following statements is correct when `SO_(2)` is passed through acidified `K_(2)Cr_(2)O_(7)` solution?

Options

A. Green `Cr_(2)(SO_(4))` is formed
B. The solution turns blue
C. The solution is decolourized
D. `SO_(2)` is reduced

Answer

A

Explanation

`K_(2)Cr_(2)O_(7) to Cr_(2)(SO_(4))_(3)` green solution obtain
whereas `SO_(2)` oxidises into sulphate `SO_(4)^(2-)`
`(K_(2)Cr_(2)O_(7) + S_(2) + H_(2)SO_(4) to Cr_(2)(SO_(4))_(3) + H_(2)O + K_(2)SO_(4))`