The product formed as a result of reaction of `CH_(3)` MgBr and `CO_(2)` on further hydrolysis gives

Options

A. `CH_(3)` COOH
B. HCOOH
C. oxalic acid
D. acetic acid

Answer

To solve the problem of what product is formed when `CH3MgBr` reacts with `CO2` and undergoes hydrolysis, we can follow these steps:

### Step 1: Identify the Reactants
The reactants are:
- `CH3MgBr` (Methylmagnesium bromide), which is a Grignard reagent.
- `CO2` (Carbon dioxide).

### Step 2: Understand the Reaction Mechanism
Grignard reagents are nucleophiles and can react with electrophiles. In this case, `CO2` acts as an electrophile. The carbon atom in `CO2` has a partial positive charge due to the electronegativity of oxygen.

### Step 3: Nucleophilic Attack
The methyl group (`CH3`) from `CH3MgBr` will attack the electrophilic carbon in `CO2`. This results in the formation of a carboxylate intermediate:
- The reaction can be represented as:
\[ CH3MgBr + CO2 \rightarrow CH3COOMgBr \]
Here, `CH3COO` is the carboxylate ion and `MgBr` is the magnesium bromide.

### Step 4: Hydrolysis of the Intermediate
Upon hydrolysis (reaction with water), the carboxylate ion will convert into a carboxylic acid:
- The hydrolysis can be represented as:
\[ CH3COOMgBr + H2O \rightarrow CH3COOH + Mg(OH)Br \]
Here, `CH3COOH` is acetic acid, and `Mg(OH)Br` is the byproduct.

### Step 5: Conclusion
The final product formed after the reaction of `CH3MgBr` with `CO2` followed by hydrolysis is acetic acid (`CH3COOH`).

### Final Answer:
The product formed as a result of the reaction of `CH3MgBr` and `CO2` on further hydrolysis is **acetic acid (CH3COOH)**.

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