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The total number of structural isomers p...

The total number of structural isomers possible for an amine with molecular formula `C_(4)H_(11)N` is

A

6

B

5

C

7

D

8

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AI Generated Solution

The correct Answer is:
To determine the total number of structural isomers for an amine with the molecular formula \( C_4H_{11}N \), we can follow these steps: ### Step 1: Identify the Degree of Unsaturation The formula to calculate the degree of unsaturation (DU) is: \[ DU = \frac{C + 1 - H + X - N}{2} \] Where: - \( C \) = number of carbon atoms - \( H \) = number of hydrogen atoms - \( X \) = number of halogens (none in this case) - \( N \) = number of nitrogen atoms For \( C_4H_{11}N \): - \( C = 4 \) - \( H = 11 \) - \( N = 1 \) Substituting these values into the formula: \[ DU = \frac{4 + 1 - 11 - 0 - 1}{2} = \frac{-7}{2} = 0 \] This indicates that there are no rings or double bonds in the structure. ### Step 2: Classify the Amines Amines can be classified as: - Primary amines (1°) - Secondary amines (2°) - Tertiary amines (3°) ### Step 3: Determine Structural Isomers for Primary Amines For primary amines, the general structure is \( RNH_2 \): 1. **Straight-chain structure**: - Butylamine: \( CH_3(CH_2)_2CH_2NH_2 \) (1 structure) 2. **Branched structures**: - Isobutylamine: \( (CH_3)_2CHCH_2NH_2 \) (1 structure) - Sec-butylamine: \( CH_3CH(CH_3)CH_2NH_2 \) (1 structure) - Tert-butylamine: \( (CH_3)_3CNH_2 \) (1 structure) Total primary amine structures = 4. ### Step 4: Determine Structural Isomers for Secondary Amines For secondary amines, the general structure is \( R_2NH \): 1. **Possible combinations**: - Ethylmethylamine: \( CH_3CH_2NHCH_3 \) (1 structure) - Dimethylamine: \( (CH_3)_2NH \) (1 structure) - Isopropylamine: \( (CH_3)CH(CH_2)NH(CH_3) \) (1 structure) Total secondary amine structures = 3. ### Step 5: Determine Structural Isomers for Tertiary Amines For tertiary amines, the general structure is \( R_3N \): 1. **Possible combinations**: - Trimethylamine: \( (CH_3)_3N \) (1 structure) - Ethylmethylamine: \( CH_3CH_2N(CH_3)CH_3 \) (1 structure) Total tertiary amine structures = 2. ### Step 6: Calculate Total Isomers Now, we can sum the total number of structural isomers: - Primary amines = 4 - Secondary amines = 3 - Tertiary amines = 2 Total structural isomers = \( 4 + 3 + 2 = 9 \). ### Final Answer The total number of structural isomers possible for an amine with the molecular formula \( C_4H_{11}N \) is **9**. ---
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