The product of the chemical reaction,
`CH_(3)-overset(O)overset(||)C-NH_(2)+Br+4NaOH to` will be

Options

A. `CH_(4)`
B. `CH_(3)Br`
C. `CH_(3)OBr`
D. `CH_(3)NH_(2)`

Answer

To solve the given chemical reaction, we will follow the steps outlined in the video transcript. The reaction involves the amide CH₃CONH₂ (acetamide) reacting with bromine (Br₂) and sodium hydroxide (NaOH).

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants are:
- CH₃CONH₂ (acetamide)
- Br₂ (bromine)
- 4 NaOH (sodium hydroxide)

2. **Understand the Role of NaOH**:
NaOH acts as a base in this reaction. It will abstract a proton (H⁺) from the amide group (NH₂) of acetamide.

3. **Deprotonation**:
The base (OH⁻ from NaOH) abstracts a proton from the nitrogen of acetamide, forming the anion CH₃CONH⁻.

4. **Nucleophilic Attack**:
The negatively charged nitrogen (from CH₃CONH⁻) attacks one of the bromine atoms in Br₂, resulting in the formation of CH₃CONHBr (bromacetamide).

5. **Formation of Imine**:
The base (OH⁻) again abstracts a proton from the nitrogen, leading to the formation of a double bond between carbon and nitrogen, yielding CH₃C=NH (an imine).

6. **Hydrolysis**:
The imine undergoes hydrolysis in the presence of water, resulting in the formation of CH₃NH₂ (methylamine) and carbon dioxide (CO₂).

7. **Side Products**:
The side products of the reaction include:
- 2 moles of NaBr (sodium bromide)
- Na₂CO₃ (sodium carbonate)
- Water (H₂O)

8. **Final Product**:
The main product of the reaction is CH₃NH₂ (methylamine).

### Summary of the Reaction:
The overall reaction can be summarized as:
\[ \text{CH}_3\text{CONH}_2 + \text{Br}_2 + 4 \text{NaOH} \rightarrow \text{CH}_3\text{NH}_2 + 2 \text{NaBr} + \text{Na}_2\text{CO}_3 + 2 \text{H}_2\text{O} \]

### Final Answer:
The product of the chemical reaction is CH₃NH₂ (methylamine).

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