In the given structure there are four chiral carbons. Hence this structure will have how many stereoisomers ? `HOH_2 C-CHOH-CHOH-CHOH-CHOH-CHO`

Options

A. `16
B. 8
C. 32
D. 4

Answer

To determine the number of stereoisomers for a compound with chiral carbons, we can follow these steps:

### Step 1: Identify the number of chiral centers
In the given structure `HOH2C-CHOH-CHOH-CHOH-CHOH-CHO`, we need to identify how many chiral carbons are present. A chiral carbon is defined as a carbon atom that is attached to four different substituents.

- In this structure, we have identified that there are **4 chiral carbons**.

### Step 2: Use the formula for calculating stereoisomers
The formula to calculate the number of stereoisomers based on the number of chiral centers (n) is given by:

\[ \text{Number of stereoisomers} = 2^n \]

### Step 3: Substitute the value of n
Since we have determined that n = 4 (the number of chiral centers), we can substitute this value into the formula:

\[ \text{Number of stereoisomers} = 2^4 \]

### Step 4: Calculate the result
Now we calculate \(2^4\):

\[ 2^4 = 16 \]

### Conclusion
Thus, the structure will have **16 stereoisomers**.

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