the equation of perpendicular bisectors of side `AB,BC` of triangle `ABC` are `x-y=5 , x+2y=0` respectively and `A(1,-2)` then coordinate of `C`

The equations of perpendicular bisectors of sides AB, BC of Delta ABC are x-y-5=0, x+2y=0 respectively and A(1,-2) then coordinates of C are

The equation of perpendicular bisectors of AB and AC of a triangle ABC are x-y-5=0 and x+2y=0 respectively. If A=(1,-2) then the equation of bar(BC) is

The equation of perpendicular bisectors of the side AB and AC of a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of triangle A B C is (in sq. units) (A) (36)/5 (B) (18)/5 (C) (72)/5 (D) None of these

The equation of perpendicular bisectors of the side AB and AC of a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of Delta A B C is (a) (36)/5 (b) (18)/5 (c) (72)/5 (d) None of these

The equation of perpendicular bisectors of the side AB and AC a triangle ABC are x-y+5=0 and x+2y=0 respectively vertex A is (1,-2) Area of triangle ABC is (in sq.units) (A) (36)/(5) (B) (18)/(5) (C) (72)/(5) (D) None of these

The equations of the perpendicular bisectors of the sides AB and AC of a triangle ABC are x -y+5=0 and x+2y=0 respectively . If the point A is (1,-2) , find the equation of the line BC.

The equations of the perpendicular bisectors of the sides AB and AC of triangle ABC are x-y+5=0 and x+2y=0, respectively.If the point A is (1,-2) ,then find the equation of the line BC .

The equation of the perpendicular bisector of the side AB of a triangle ABC is x - y + 5 = 0. If the point A is (1,-2), find the co-ordinates of the point B.