In which of the following erythroblastosis foetalis is possible in their second progeny

Options

A. Rh+male and Rh+female
B. Rh+male and Rh-female
C. Rh+male and Rh+female
D. Rh-male and Rh+female

Answer

### Step-by-Step Solution:

1. **Understanding Erythroblastosis Foetalis**:
- Erythroblastosis foetalis is a condition where the fetus suffers from hemolytic anemia due to incompatibility between the blood types of the mother and the fetus. This often occurs when the mother is Rh-negative and the fetus is Rh-positive.

2. **First Pregnancy**:
- In the first pregnancy, if the mother is Rh-negative and the fetus is Rh-positive, the mother’s immune system does not usually react because there is no significant mixing of blood between the mother and the fetus during pregnancy. Thus, the first child is typically born healthy.

3. **Second Pregnancy**:
- If the mother becomes pregnant again with another Rh-positive fetus, her immune system may have developed antibodies against Rh-positive blood from the first pregnancy. If these antibodies cross the placenta, they can attack the red blood cells of the second fetus, leading to erythroblastosis foetalis.

4. **Analyzing the Options**:
- **Option 1**: Rh positive male and Rh positive female - No risk of erythroblastosis foetalis as both parents are Rh-positive.
- **Option 2**: Rh positive male and Rh negative female - This is a potential risk if the second child is Rh-positive, as the mother can develop antibodies from the first Rh-positive child.
- **Option 3**: Rh positive male and Rh positive female - Same as option 1, no risk.
- **Option 4**: Rh negative male and Rh positive female - There is no risk of erythroblastosis foetalis as the mother is Rh-positive.

5. **Conclusion**:
- The condition of erythroblastosis foetalis is possible in the second progeny if the mother is Rh-negative and the father is Rh-positive, making **Option 2** the correct answer.