What is the inheritance of colour blindness of both parents having a normal vision but mother has a recessive gene for colour blindness :

Options

A. `{:("Son"," Daugther"),(50%," Nil"):}`
B. `{:("Son"," Daugther"),(100%," Nil"):}`
C. `{:("Son"," Daugther"),("Nil", " "100%):}`
D. `{:("Son"," Daugther"),("Nil", " Nil"):}`

Answer

To solve the question regarding the inheritance of color blindness in a scenario where both parents have normal vision but the mother carries a recessive gene for color blindness, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Genetic Basis of Color Blindness**:
- Color blindness is a sex-linked recessive disorder, meaning the gene responsible for it is located on the X chromosome. Males (XY) are more likely to be affected because they have only one X chromosome.

**Hint**: Remember that sex-linked traits are often inherited differently in males and females due to their different sex chromosomes.

2. **Determine the Genotypes of the Parents**:
- The mother has normal vision but carries a recessive gene for color blindness. Therefore, her genotype is X^cX (where X^c represents the X chromosome with the color blindness allele).
- The father has normal vision and does not carry the gene for color blindness, so his genotype is XY.

**Hint**: Use X and Y to represent the sex chromosomes, and use superscripts to denote alleles (e.g., X^c for color blindness).

3. **Set Up a Punnett Square**:
- Create a Punnett square to predict the genotypes of the offspring. The mother can pass on either X^c or X, while the father can pass on either X or Y.

**Hint**: A Punnett square helps visualize the combinations of alleles that offspring can inherit from their parents.

4. **Analyze the Possible Offspring**:
- The possible combinations from the Punnett square are:
- Daughter: X^cX (carrier, normal vision)
- Daughter: XX (normal vision)
- Son: X^cY (affected by color blindness)
- Son: XY (normal vision)

**Hint**: Remember that daughters inherit one X chromosome from each parent, while sons inherit one X from the mother and one Y from the father.

5. **Calculate the Ratios**:
- From the combinations, we can see that:
- 50% of daughters are carriers (X^cX) and 50% are normal (XX).
- 50% of sons are affected (X^cY) and 50% are normal (XY).

**Hint**: Ratios help summarize the likelihood of different genotypes and phenotypes in the offspring.

6. **Conclusion**:
- In summary, 50% of the sons will be affected by color blindness, and none of the daughters will be affected, although 50% will be carriers.

**Hint**: Always conclude by summarizing the key findings of your genetic analysis.

### Final Answer:
- In this scenario, 50% of the sons will be affected by color blindness, and 50% of the daughters will be carriers, but none will be affected.