`sin(A+B)=sin A+sin B`

sin(B+C-A)+sin(C+A-B)+sin(A+B-C)=4sin A sin B sin C

In triangle ABC, prove that sin(B+C-A)+sin(C+A-B)+sin(A+B-C)=4sin A sin B sin C .

Show that (1+sin A)/(cos A)+(cos B)/(1-sin B)=(2sin A-2sin B)/(sin(A-B)+cos A-cos B)

Prove by vector method that sin(A-B)=sin A cos B-cos A sin B and sin(A+B)=sin A cos B+cos A sin B

If A=B=60o, verify that cos(A-B)=cos A cos B+sin A sin B(iii)sin(A-B)=sin A cos B-cos A sin B(iii)tan(A-B)=(tan A-tan B)/(1+tan A tan B)

Prove (i)sin(A+B)+sin(A-B)=2sin A cos B (ii) sin(A+B)-sin(A-B)=2cos A sin B

For all values of angle A and B(i)sin(A-B)=sin A cos B-cos A sin B(ii)sin(A+B)=sin A cos B+cos A sin B

sin A sin (A + 2B) sin B sin (B + 2A) = sin (AB) sin (A + B)

(sin A + sin B) / (sin A-sin B) = tan ((A + B) / (2)) cot ((AB) / (2))

sin(A+B).sin(A- B)=sin^(2)A-sin^(2)B