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Find the smallest number by which 252 mu...

Find the smallest number by which `252` must be multiplied to get a perfect square. Also, find the square root of the perfect square so obtained.

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To solve the problem of finding the smallest number by which 252 must be multiplied to get a perfect square, and also to find the square root of the perfect square obtained, we can follow these steps: ### Step 1: Factor the number 252 First, we need to find the prime factorization of 252. - Divide 252 by 2: \( 252 \div 2 = 126 \) - Divide 126 by 2: \( 126 \div 2 = 63 \) - Divide 63 by 3: \( 63 \div 3 = 21 \) - Divide 21 by 3: \( 21 \div 3 = 7 \) - Finally, 7 is a prime number. So, the prime factorization of 252 is: \[ 252 = 2^2 \times 3^2 \times 7^1 \] ### Step 2: Identify the factors for forming pairs In order to form a perfect square, all prime factors must have even powers. - From the factorization \( 2^2 \times 3^2 \times 7^1 \): - The powers of 2 and 3 are already even (2 and 2). - The power of 7 is odd (1). ### Step 3: Determine the smallest number to multiply To make the power of 7 even, we need to multiply by one more 7. Thus, we need to multiply 252 by 7 to make it a perfect square. So, the smallest number by which 252 must be multiplied is: \[ 7 \] ### Step 4: Calculate the perfect square Now, we multiply 252 by 7: \[ 252 \times 7 = 1764 \] ### Step 5: Find the square root of the perfect square Next, we need to find the square root of 1764. We can use the prime factorization we found earlier: - The prime factorization of 1764 is: \[ 1764 = 2^2 \times 3^2 \times 7^2 \] To find the square root, we take half of the powers of the prime factors: \[ \sqrt{1764} = 2^{2/2} \times 3^{2/2} \times 7^{2/2} = 2^1 \times 3^1 \times 7^1 = 2 \times 3 \times 7 \] Calculating this gives: \[ 2 \times 3 = 6 \] \[ 6 \times 7 = 42 \] Thus, the square root of the perfect square 1764 is: \[ 42 \] ### Final Answer - The smallest number by which 252 must be multiplied to get a perfect square is: **7** - The square root of the perfect square obtained (1764) is: **42** ---
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