Home
Class 8
MATHS
Evaluate: sqrt (75.69)...

Evaluate:
`sqrt (75.69)`

Text Solution

AI Generated Solution

The correct Answer is:
To evaluate \( \sqrt{75.69} \), we can follow these steps: ### Step 1: Remove the Decimal To make calculations easier, we can remove the decimal by multiplying the number by 100. Thus, we rewrite \( 75.69 \) as \( 7569 \) (since \( 75.69 \times 100 = 7569 \)). ### Step 2: Find the Square Root Now, we need to find the square root of \( 7569 \). We can do this through prime factorization or long division. Here, we will use the prime factorization method. ### Step 3: Prime Factorization of 7569 To find the prime factors of \( 7569 \): - Start dividing \( 7569 \) by the smallest prime number, which is \( 3 \): - \( 7569 \div 3 = 2523 \) - Continue dividing \( 2523 \) by \( 3 \): - \( 2523 \div 3 = 841 \) - Now, \( 841 \) is not divisible by \( 3 \), so we check the next prime number, which is \( 29 \): - \( 841 \div 29 = 29 \) - Thus, the prime factorization of \( 7569 \) is \( 3^2 \times 29^2 \). ### Step 4: Taking the Square Root Now we can take the square root of \( 7569 \): - \( \sqrt{7569} = \sqrt{3^2 \times 29^2} = 3 \times 29 = 87 \). ### Step 5: Applying the Decimal Since we multiplied by \( 100 \) in the first step, we need to apply the decimal back: - The square root of \( 75.69 \) is \( 87 \). ### Final Answer Thus, \( \sqrt{75.69} = 8.7 \).
Promotional Banner

Topper's Solved these Questions

  • SQUARES

    RS AGGARWAL|Exercise EXERCISE 3G|10 Videos
  • SQUARES

    RS AGGARWAL|Exercise EXERCISE 3H|19 Videos
  • SQUARES

    RS AGGARWAL|Exercise EXERCISE 3E|19 Videos
  • RATIONAL NUMBERS

    RS AGGARWAL|Exercise TEST PAPER|19 Videos
  • THREE - DIMENSIONAL FIGURES

    RS AGGARWAL|Exercise EXERCISE 19 B|5 Videos

Similar Questions

Explore conceptually related problems

Evaluate: sqrt (1.69)

Evaluate: 69xx71

Given that sqrt(5625) =75 , the value of sqrt(0.5625) + sqrt(56.25) is:

Find the value of sqrt 75+ sqrt 48+ sqrt 12

32.Give that sqrt(3)=1.732 find the value of sqrt(75)+(1)/(2)sqrt(48)-sqrt(192)

Using suitable identity evaluate the (69.3) ^(2) - (30.7) ^(2)

Evaluate : ""^(75)C_(73)

If alpha is a root of equation (1) and beta is a root of (2), ten tanalpha+tanbetas may be equal to (A) 1+sqrt(69)/6 (B) 1+2sqrt(69)/6 (C) (3+sqrt(69))/6 (D) (-3-sqrt(69))/3

If sqrt(3)=1.732, find the value of sqrt(192)-(1)/(2)sqrt(48)-sqrt(75) correct to 3 places of decimal.