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If the roots of equation (a + 1)x^2-3ax ...

If the roots of equation `(a + 1)x^2-3ax + 4a = 0` (a is not equals to -1) are greater than unity, then

A

`[-(10)/(7),1]`

B

`[-(12)/(7),0]`

C

`[-(16)/(7),-1)`

D

`(-(16)/(7),0)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(c )` `(a+1)x^(2)-3ax+4a=0`
`D=9a^(2)-16a(a+1) ge 0` ………`(i)`
`x_(1) gt 1`, `x_(2) gt 1`
`:. (a+1)f(1) gt 0` and `(3a)/(2(a+1)) gt 1`
`implies(a+1)(2a+1) gt 0`
and `(a-2)/(a+1) gt 0` ……..`(ii)`
`(2a+1)/(a+1) gt 0`………`(iii)`
Solving `(i)`, `(ii)` and `(iii)`, we get `-(16)/(7) le a lt -1`.
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